document.write( "Question 938257: the areas of two similar tetrahedrons are 24 square inches and 96 square inches. find the ratio of their volumes
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Algebra.Com's Answer #573128 by macston(5194)\"\" \"About 
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This method works only for regular tetrahedra. Not enough info is given to calculate for irregular tetrahedra.\r
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\n" ); document.write( "\n" ); document.write( "The formula for surface area of a regular tetrahedron is \"SA=sqrt%283%29a%5E2\"\r
\n" ); document.write( "\n" ); document.write( "In this case we have:\r
\n" ); document.write( "\n" ); document.write( "\"24=sqrt%283%29a%5E2\" solving for a:\r
\n" ); document.write( "\n" ); document.write( "\"a%5E2=24%2Fsqrt%283%29\"
\n" ); document.write( "\"a=sqrt%2824%2Fsqrt%283%29%29\"
\n" ); document.write( "a=3.72 (approx.)
\n" ); document.write( "and\r
\n" ); document.write( "\n" ); document.write( "\"a%5E2=96%2Fsqrt%283%29\"
\n" ); document.write( "\"a=sqrt%2896%2Fsqrt%283%29%29\"
\n" ); document.write( "a=7.44 (approx.)\r
\n" ); document.write( "\n" ); document.write( "The volume for a regular tetrahedron is \"a%5E3%2F%286%28Sqrt%282%29%29%29\"\r
\n" ); document.write( "\n" ); document.write( "V(1) = \"%283.72%5E3%29%2F%286sqrt%282%29%29\" = 6.07
\n" ); document.write( "V(2) = \"%287.44%5E3%29%2F%286sqrt%282%29%29\" = 48.53\r
\n" ); document.write( "\n" ); document.write( "The ratio of volumes =V(1)/V(2) =6.07/48.53= 0.125 = 1:8
\n" ); document.write( "Note the ratio of edge length=1:2 or \"%281%2F2%29\"
\n" ); document.write( " the ratio of surface area=1:4 or \"%281%2F2%29%5E2\"
\n" ); document.write( " the ratio of volumes=1:8 or \"%281%2F2%29%5E3\"
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