document.write( "Question 10900: 4x-2
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\n" ); document.write( " 5 \r
\n" ); document.write( "\n" ); document.write( "Please help me answer this guestion: 4x-2 all over 5 greater than or equal
\n" ); document.write( "to -4
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Algebra.Com's Answer #5731 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
\"%284x-2%29%2F5+%3E=+-4\" Multiply both sides by 5.\r
\n" ); document.write( "\n" ); document.write( "\"4x-2+%3E=+-20\" Add 2 to both sides.\r
\n" ); document.write( "\n" ); document.write( "\"4x+%3E=+-18\" Divide both sides by 4.\r
\n" ); document.write( "\n" ); document.write( "\"x+%3E=+4.5\"
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