document.write( "Question 940261: One number is six more than another number, the sum of their squares is 90? \n" ); document.write( "
Algebra.Com's Answer #573058 by ankor@dixie-net.com(22740)\"\" \"About 
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let the two numbers be a & b
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\n" ); document.write( "Write an equation for each statement
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\n" ); document.write( "One number is six more than another number,
\n" ); document.write( "a = b + 6
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\n" ); document.write( " the sum of their squares is 90?
\n" ); document.write( "a^2 + b^2 = 90
\n" ); document.write( "Replace a with (b+6)
\n" ); document.write( "(b+6)^2 + b^2 = 90
\n" ); document.write( "FOIL (b+6)(b+6)
\n" ); document.write( "b^2 + 6b + 6b + 36 + b^2 = 90
\n" ); document.write( "Combine like terms, write as a quadratic equation
\n" ); document.write( "b^2 + b^2 + 12b + 36 - 90 = 0
\n" ); document.write( "2b^2 + 12b - 54 = 0
\n" ); document.write( "simplify, divide by 2
\n" ); document.write( "b^2 + 6b - 27 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(b+9)(b-3) = 0
\n" ); document.write( "two solutions
\n" ); document.write( "b = -9
\n" ); document.write( "b = +3
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\n" ); document.write( "find a when b = -9
\n" ); document.write( "a - (-9) = 6
\n" ); document.write( "a + 9 = 6
\n" ); document.write( "a = 6 - 9
\n" ); document.write( "a = -3
\n" ); document.write( "find a when b = 3
\n" ); document.write( "a - 3 = 6
\n" ); document.write( "a = 6 + 3
\n" ); document.write( "a = 9
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\n" ); document.write( "Summarize: a=-3; b=-9. Or a=9; b=3
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