document.write( "Question 940261: One number is six more than another number, the sum of their squares is 90? \n" ); document.write( "
Algebra.Com's Answer #573058 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! let the two numbers be a & b \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement \n" ); document.write( ": \n" ); document.write( "One number is six more than another number, \n" ); document.write( "a = b + 6 \n" ); document.write( ": \n" ); document.write( " the sum of their squares is 90? \n" ); document.write( "a^2 + b^2 = 90 \n" ); document.write( "Replace a with (b+6) \n" ); document.write( "(b+6)^2 + b^2 = 90 \n" ); document.write( "FOIL (b+6)(b+6) \n" ); document.write( "b^2 + 6b + 6b + 36 + b^2 = 90 \n" ); document.write( "Combine like terms, write as a quadratic equation \n" ); document.write( "b^2 + b^2 + 12b + 36 - 90 = 0 \n" ); document.write( "2b^2 + 12b - 54 = 0 \n" ); document.write( "simplify, divide by 2 \n" ); document.write( "b^2 + 6b - 27 = 0 \n" ); document.write( "Factors to \n" ); document.write( "(b+9)(b-3) = 0 \n" ); document.write( "two solutions \n" ); document.write( "b = -9 \n" ); document.write( "b = +3 \n" ); document.write( ": \n" ); document.write( "find a when b = -9 \n" ); document.write( "a - (-9) = 6 \n" ); document.write( "a + 9 = 6 \n" ); document.write( "a = 6 - 9 \n" ); document.write( "a = -3 \n" ); document.write( "find a when b = 3 \n" ); document.write( "a - 3 = 6 \n" ); document.write( "a = 6 + 3 \n" ); document.write( "a = 9 \n" ); document.write( ": \n" ); document.write( "Summarize: a=-3; b=-9. Or a=9; b=3 \n" ); document.write( " |