document.write( "Question 79876: Log(base4)(2x+1)=Log(base4)(x-3)+Log(base4)(x+5) \n" ); document.write( "

Algebra.Com's Answer #57304 by Nate(3500) $\"\"$ $\"About$

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$\"log%284%2C2x+%2B+1%29+=+log%284%2Cx+-+3%29+%2B+log%284%2Cx+%2B+5%29\"$
\n" ); document.write( " $\"log%284%29%282x+%2B+1%29+=+log%284%2C%28x+-+3%29%28x+%2B+5%29%29\"$
\n" ); document.write( " $\"log%284%29%282x+%2B+1%29+=+log%284%2Cx%5E2+%2B+2x+-+15%29\"$
\n" ); document.write( " $\"2x+%2B+1+=+x%5E2+%2B+2x+-+15\"$
\n" ); document.write( " $\"0+=+x%5E2+-+16\"$
\n" ); document.write( " $\"0+=+%28x+%2B+4%29%28x+-+4%29\"$
\n" ); document.write( "x = -4 and x = 4
\n" ); document.write( "You can not take a log of a negative number. Answer: x = 4
\n" ); document.write( " \n" ); document.write( "

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