document.write( "Question 939809: it's actually about calculus but i couldn't find any parts about it..
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document.write( "i was solving integration of tan^-1(x) by parts :
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document.write( "consider ∫tan^-1(x)x1 dx.
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document.write( "so let u=tan^-1(x) and du/dx=1/(1^2+x^2)
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document.write( " dv/dx=1, so v=x.
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document.write( "∫tan^-1(x)dx = xtan^-1(x)-∫(1/(1+x^2))(x)dx
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document.write( " = xtan^-1(x)-∫(x/(1+x^2)dx
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document.write( " = xtan^-1(x)-(1/2)∫(2x/(1+x^2))dx
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document.write( " = xtan^-1(x)-(1/2)tan^-1(x^2)+c.
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document.write( "but the answer is xtan^-1(x)-(1/2)ln(1+(x^2))+c.
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document.write( " Why??? \n" );
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Algebra.Com's Answer #573011 by richard1234(7193)![]() ![]() You can put this solution on YOUR website! Note the integration by parts formula: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In this case, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Integrating |