document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=940186>Question 940186</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if 12 men can dig a trench in 8 days, how many men can dig it in 6 days at the same rate?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #572988 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=572988\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if 12 men can dig a trench in 8 days, how many men can dig it in 6 days at the same rate?<BR>\n" );
document.write( "Let x=number of men needed to dig trench in 6 days<BR>\n" );
document.write( "then x men digs at the rate of 1/6 trench per day<BR>\n" );
document.write( "and 1 man digs at the rate of (1/6)/x=1/6x trench per day<BR>\n" );
document.write( "12 men digs at the rate of 1/8 trench per day<BR>\n" );
document.write( "1 man digs at the rate of (1/8)/12=1/96 trench per day<BR>\n" );
document.write( "Soooo, (1/6x)=1/96<BR>\n" );
document.write( "6x=96<BR>\n" );
document.write( "x=16 men---number needed to dig trench in 6 days<BR>\n" );
document.write( "Does this help?---ptaylor </SPAN>\n" );
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