document.write( "Question 940120: Jenny, who rides a moped, takes 2 hours less to travel 60 miles than Maureen takes to travel 50 miles on her bicycle. Jenny travels 10 miles per hour faster than Maureen. (Hint: speed = distance ÷ time.)\r
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Algebra.Com's Answer #572932 by stanbon(75887)\"\" \"About 
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Jenny, who rides a moped, takes 2 hours less to travel 60 miles than Maureen takes to travel 50 miles on her bicycle. Jenny travels 10 miles per hour faster than Maureen. (Hint: speed = distance ÷ time.)
\n" ); document.write( " How fast is Jenny and Maureen going in mph?
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\n" ); document.write( "Jenny DATA:
\n" ); document.write( "dist = 60 miles ; time = x-2 hrs ; rate = d/t = 60/(x-2) mph
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\n" ); document.write( "Maureen DATA:
\n" ); document.write( "dist = 50 miles ; time = x hrs ; rate = d/t = 50/x mph
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\n" ); document.write( "Equation:
\n" ); document.write( "Jenny rate - Maureen rate = 10 mph
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\n" ); document.write( "60/(x-2) - 50/x = 10 mph
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\n" ); document.write( "60x - 50(x-2) = 10x(x-2)
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\n" ); document.write( "10x + 100 = 10x^2 - 20x
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\n" ); document.write( "x + 10 = x^2 - 2x
\n" ); document.write( "x^2 - 3x - 10 = 0
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\n" ); document.write( "(x-5)(x+2) = 0
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 5 hrs
\n" ); document.write( "Jenny rate = 60/3 = 20 mph
\n" ); document.write( "Maureen rate = 50/5 = 10 mph
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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