document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=940076>Question 940076</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a tea shop owner wishes to blend P2.50/g tea with P3.25/g to produce a blend selling for P3/g.how much of each should be used to produce 7.5 kg of the blend<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #572881 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=572881\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 	Price	----------------			quantity									<BR>\n" );
document.write( "Tea type I	P2.50	----------------			x	gm								<BR>\n" );
document.write( "Tea type II	P3.25	------	7500	-	x	gm								<BR>\n" );
document.write( "Mixture	P3.00	----------------	7500											<BR>\n" );
document.write( "Total	7500		gm											<BR>\n" );
document.write( "2.5	x	+	3.25	(	7500	-	x	)	=	22500				<BR>\n" );
document.write( "2.5	x	+	24375	-	3.25	x	=			22500				<BR>\n" );
document.write( "2.5	x	-	3.25	x			=	22500	-	-24375				<BR>\n" );
document.write( "-0.75	x			=	-1875									<BR>\n" );
document.write( "/	-0.75													<BR>\n" );
document.write( "	x			=	2500		gm			P2.50		Tea type I		<BR>\n" );
document.write( "					5000		gm			P3.25		Tea type II		<BR>\n" );
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document.write( "m.ananth@hotmail.ca														<BR>\n" );
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