Algebra.Com's Answer #572858 by MathTherapy(10552)  You can put this solution on YOUR website! Find the rule of a quadratic function if it has a minimum value of y=4, an axis of symmetry at x=3 and passes through point (4,-3) \n" );
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document.write( "Vertex form of a parabolic equation:  \n" );
document.write( "With: \n" );
document.write( "x being 4 \n" );
document.write( "y being - 3 \n" );
document.write( "h being 3, and \n" );
document.write( "k being 4, this becomes:  \n" );
document.write( "- 3 = a + 4 \n" );
document.write( "a = - 3 - 4, or - 7 \n" );
document.write( "Rule, or equation: \r \n" );
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document.write( "This is IMPOSSIBLE. For a parabola to have a vertex of (3, 4) and pass through the point, (4, - 3), it \n" );
document.write( "WILL HAVE a MAXIMUM, not a MINIMUM. If it does have a MINIMUM at (3, 4), it will open UPWARDS, and therefore, \n" );
document.write( "will NEVER pass through the point (4, - 3), which by the way is a point in the 2nd quadrant. In other words, \n" );
document.write( "its range would be \r \n" );
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document.write( "The above equation represents what the problem states, with the exception that the graph will have a MAXIMA \n" );
document.write( "instead of a MINIMA, as stated before. \n" );
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