document.write( "Question 940015: 3-x>3x+11 \n" ); document.write( "

Algebra.Com's Answer #572852 by srinivas.g(540) $\"\"$ $\"About$

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3-x> 3x+11
\n" ); document.write( " add x on both sides
\n" ); document.write( " 3-x+x>3x+11+x
\n" ); document.write( " 3>4x+11
\n" ); document.write( "move 11 to the left
\n" ); document.write( " 3-11>4x
\n" ); document.write( " -8>4x
\n" ); document.write( " divide with 4 on both sides
\n" ); document.write( " $\"-8%2F4%3E4x%2F4\"$
\n" ); document.write( "-2>x
\n" ); document.write( "result: x<-2
\n" ); document.write( " \n" ); document.write( "

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