document.write( "Question 939969: A salesman drives from Ajax to Barrington, a distance of 140 mi, at a steady speed. He then increases his speed by 15 mi/h to drive the 180 mi from Barrington to Collins. If the second leg of his trip took 4 min more time than the first leg, how fast was he driving between Ajax and Barrington?
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Algebra.Com's Answer #572836 by ankor@dixie-net.com(22740)\"\" \"About 
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A salesman drives from Ajax to Barrington, a distance of 140 mi, at a steady speed.
\n" ); document.write( " He then increases his speed by 15 mi/h to drive the 180 mi from Barrington to Collins.
\n" ); document.write( " If the second leg of his trip took 4 min more time than the first leg,how fast was he driving between Ajax and Barrington?
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\n" ); document.write( "let s = his original speed
\n" ); document.write( "(s+15) = his increased speed
\n" ); document.write( "then
\n" ); document.write( "\"140%2Fs\" time from Aj to Bar
\n" ); document.write( "and
\n" ); document.write( "\"180%2F%28%28s%2B15%29%29\" = time from Bar to Col
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\n" ); document.write( "Bar/Col time - Aj/Bar time = 4 min
\n" ); document.write( "\"180%2F%28%28s%2B15%29%29\" - \"140%2Fs\" = \"4%2F60\" (we have to convert 4 min to hrs)
\n" ); document.write( "\"180%2F%28%28s%2B15%29%29\" - \"140%2Fs\" = \"1%2F15\" (reduce the fraction)
\n" ); document.write( "multiply equation by 15s(s+15), cancel the denominators and you have
\n" ); document.write( "15s(180) - 15(s+15)(140) = s(s+15)
\n" ); document.write( "2700s - (15s+225)(140) = s^2 + 15s
\n" ); document.write( "2700s - 2100s - 31500 = s^2 + 15s
\n" ); document.write( "600s - 31500 = s^2 + 15s
\n" ); document.write( "Combine on the right to form a quadratic equation
\n" ); document.write( "0 = s^2 + 15s - 600s + 31500
\n" ); document.write( "0 = s^2 - 585s + 31500
\n" ); document.write( "you can use the quadratic formula here a=1; b=-585; c=31500. however this will factor
\n" ); document.write( "(s-525)(s-60) = 0
\n" ); document.write( "s = 525, not reasonable
\n" ); document.write( "s = 60 mph, his speed from Aj to Bar
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\n" ); document.write( "See if that checks out; (Bar/Col speed is 15 mph more or 75 mph)
\n" ); document.write( "180/75 = 2.40 hrs
\n" ); document.write( "140/60 = 2.3333 hrs
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\n" ); document.write( "differs by .067 hrs, convert to min; .067(60) ~ 4.0 min\r
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