document.write( "Question 939969: A salesman drives from Ajax to Barrington, a distance of 140 mi, at a steady speed. He then increases his speed by 15 mi/h to drive the 180 mi from Barrington to Collins. If the second leg of his trip took 4 min more time than the first leg, how fast was he driving between Ajax and Barrington?
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Algebra.Com's Answer #572836 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A salesman drives from Ajax to Barrington, a distance of 140 mi, at a steady speed. \n" ); document.write( " He then increases his speed by 15 mi/h to drive the 180 mi from Barrington to Collins. \n" ); document.write( " If the second leg of his trip took 4 min more time than the first leg,how fast was he driving between Ajax and Barrington? \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "let s = his original speed \n" ); document.write( "(s+15) = his increased speed \n" ); document.write( "then \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Bar/Col time - Aj/Bar time = 4 min \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "multiply equation by 15s(s+15), cancel the denominators and you have \n" ); document.write( "15s(180) - 15(s+15)(140) = s(s+15) \n" ); document.write( "2700s - (15s+225)(140) = s^2 + 15s \n" ); document.write( "2700s - 2100s - 31500 = s^2 + 15s \n" ); document.write( "600s - 31500 = s^2 + 15s \n" ); document.write( "Combine on the right to form a quadratic equation \n" ); document.write( "0 = s^2 + 15s - 600s + 31500 \n" ); document.write( "0 = s^2 - 585s + 31500 \n" ); document.write( "you can use the quadratic formula here a=1; b=-585; c=31500. however this will factor \n" ); document.write( "(s-525)(s-60) = 0 \n" ); document.write( "s = 525, not reasonable \n" ); document.write( "s = 60 mph, his speed from Aj to Bar \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if that checks out; (Bar/Col speed is 15 mph more or 75 mph) \n" ); document.write( "180/75 = 2.40 hrs \n" ); document.write( "140/60 = 2.3333 hrs \n" ); document.write( "----------------- \n" ); document.write( "differs by .067 hrs, convert to min; .067(60) ~ 4.0 min\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |