document.write( "Question 939927: Suppose 10% of the population is left-handed. What’s the probability of
\n" ); document.write( "seeing at most three left-handed students in a class of size 30?
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Algebra.Com's Answer #572829 by mathmate(429)\"\" \"About 
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\n" ); document.write( "Given:
\n" ); document.write( "Assume class is a random sample with respect to left-handedness.
\n" ); document.write( "population is 10% left-handed, i.e. probability p=0.10 is constant.
\n" ); document.write( "The number of steps of the experiment is known, n=30.
\n" ); document.write( "Each step is a Bernoulli experiment, i.e. with one of two possible outcomes.
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\n" ); document.write( "Under these conditions, the binomial distribution applies.
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\n" ); document.write( "Let P(X=r) be the probability of having r successes, then
\n" ); document.write( "P(X<=3) = P(X=0) + P(X=1) + P(X=2) + P(X=3)
\n" ); document.write( "where
\n" ); document.write( "P(X=r) = \"C%28n%2Cr%29%2Ap%5Er%2A%281-p%29%5E%28n-r%29\"
\n" ); document.write( "C(n,r) = \"n%21%2F%28%28n-r%29%21%2Ar%21%29\" is combination of r objects out of n
\n" ); document.write( "n = 30 = number steps of experiment
\n" ); document.write( "p = 0.1 = probability of success (left-handed)
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\n" ); document.write( "P(X<=3) = P(X=0) + P(X=1) + P(X=2) + P(X=3)
\n" ); document.write( "=
\n" ); document.write( "= \"0.0424+%2B+0.1413+%2B+0.2277+%2B+0.2361\"
\n" ); document.write( "= \"0.6474\"
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\n" ); document.write( "Answer: the probability of seeing up to 3 left-handed students is 0.6474\r
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