document.write( "Question 939954: If \"3%5Ex%2B4%5Ex+=+5%5Ex\" Find x. NB:x is 2 but I need the method, thanks \n" ); document.write( "
Algebra.Com's Answer #572817 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "recall the Pythagorean formula
\n" ); document.write( "\"a%5E2%2Bb%5E2+=+c%5E2\"\r
\n" ); document.write( "\n" ); document.write( "you have \"3%5Ex%2B4%5Ex+=+5%5Ex\", means \"a=3\",\"b=4\", and \"c=5\" which are sides of the Right-Angled Triangle; so, \"x\" must be \"2\"\r
\n" ); document.write( "\n" ); document.write( "answer: \"x=2\", from the Pythagorean formula for the Right-Angled Triangle
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