document.write( "Question 939868: 2p(p^3^ +1). = ? Where p = -2 \n" ); document.write( "
Algebra.Com's Answer #572744 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
this part p^3^ is confusing; I guess you have only \"p%5E3\"\r
\n" ); document.write( "\n" ); document.write( "\"2p%28p%5E3+%2B1%29\" if\"+p+=+-2\", then we have\r
\n" ); document.write( "\n" ); document.write( "\"2%28-2%29%28%28-2%29%5E3+%2B1%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"-4%28highlight%28%28-2%29%28-2%29%28-2%29%29+%2B1%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"-4%28highlight%28%28-2%29%28-2%29%29%28-2%29+%2B1%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"-4%28%28highlight%284%29%28-2%29%29+%2B1%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"-4%28highlight%284%28-2%29%29+%2B1%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"-4%28highlight%28-8%29+%2B1%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"-4%28-7%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"28\"
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