document.write( "Question 939772: How do I figure out the smallest surface area of a cylinder when I only know what the volume is? the volume is 50,000cm cubed. \n" ); document.write( "
Algebra.Com's Answer #572721 by KMST(5328)\"\" \"About 
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If you need to design a cylinder with a volume of \"%2250%2C000%22\"\"cm%5E3\" ,
\n" ); document.write( "you could start with
\n" ); document.write( "\"R\"= radius of the bases of the cylinder, and
\n" ); document.write( "\"H\"= height of the cylinder,
\n" ); document.write( "both in \"cm\" .
\n" ); document.write( "The volume in \"cm%5E3\" is calculated as
\n" ); document.write( "\"pi%2AR%5E2%2AH\" .
\n" ); document.write( "If that volume is \"%2250%2C000%22\"\"cm%5E3\" , then
\n" ); document.write( "\"pi%2AR%5E2%2AH=%2250%2C000%22\"-->\"H=%2250%2C000%22%2F%28pi%2AR%5E2%29\" .
\n" ); document.write( "Now, if you make it a right cylinder
\n" ); document.write( "(one with its axis perpendicular to the bases,
\n" ); document.write( "the total surface area is calculated as
\n" ); document.write( "\"A=2pi%2AR%5E2%2B2pi%2AR%2AH\" .
\n" ); document.write( "Substituting \"H=%2250%2C000%22%2F%28pi%2AR%5E2%29\" into the equation above, we get
\n" ); document.write( "\"A=2pi%2AR%5E2%2B2pi%2AR%2A%28%2250%2C000%22%2F%28pi%2AR%5E2%29%29\"
\n" ); document.write( "\"A=2pi%2AR%5E2%2B2%2A%2250%2C000%22%2F%28pi%2AR%29%29\"
\n" ); document.write( "\"A=2pi%2AR%5E2%2B%22100%2C000%22%2F%28pi%2AR%29%29\"
\n" ); document.write( "The area as a function of radius of the cylinder
\n" ); document.write( "is very large for
\n" ); document.write( "very narrow (and very tall) cylinders, and for
\n" ); document.write( "very short and very wide) cylinders with the same area
\n" ); document.write( "Its graph looks like this
\n" ); document.write( "\"graph%28300%2C300%2C-10%2C40%2C-1000%2C9000%2C2pi%2Ax%5E2%2B100000%2F%28pi%2Ax%29%29\"
\n" ); document.write( "In the middle, there is a value for the radius that makes the surface are as small as possible.
\n" ); document.write( "How would you find that value for the radius, and the minimum area?
\n" ); document.write( "Maybe you are expected to use a graphing calculator.
\n" ); document.write( "Maybe you are studying calculus.
\n" ); document.write( "and are expected to calculate the derivative of the function
\n" ); document.write( "\"A=2pi%2AR%5E2%2B%22100%2C000%22%2F%28pi%2AR%29%29\" ,
\n" ); document.write( "and find the \"R\" value where that derivative is zero ans \"A\" is minimum.
\n" ); document.write( "The derivative is
\n" ); document.write( "\"dA%2FdR=4pi%2AR-100000%2F%28pi%2AR%5E2%29\"<-->\"dA%2FdR=%284pi%5E2%2AR%5E3-100000%29%2F%28pi%2AR%5E2%29\"
\n" ); document.write( "and that is zero when
\n" ); document.write( "\"4pi%5E2%2AR%5E3=100000\"-->\"R%5E3=100000%2F4pi%5E2\"-->\"R=root%283%2C100000%2F4pi%5E2%29\"-->\"R=13.63%28rounded%29\" ,
\n" ); document.write( "and the approximate value for the minimum area (in cubic cm)
\n" ); document.write( "(when \"R\" takes that value) is
\n" ); document.write( "\"A=3502.6\"
\n" ); document.write( "
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