document.write( "Question 939786: This is more of a word problem but I am stuck on how to figure it out. Thanks in advance!\r
\n" ); document.write( "\n" ); document.write( "The shortest side of an isosceles triangle is 19 cm less than twice as long as the other sides. The perimeter of the triangle is 49 cm. Find the lengths of the three sides.
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Algebra.Com's Answer #572717 by KMST(5328)\"\" \"About 
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\"highlight%2815cm%29\" , \"highlight%2817cm%29\" , and \"highlight%2817cm%29\" ,
\n" ); document.write( "\"x\"= the length (in cm) of the two congruent sides (the \"other sides\").
\n" ); document.write( "\"2x-19\"= the length (in cm) of the shortest side (which is \"19 cm less than twice as long as the other sides\").
\n" ); document.write( "The perimeter (in cm) is
\n" ); document.write( "\"%282x-19%29%2Bx%2Bx=49\"
\n" ); document.write( "Solving for \"x\":
\n" ); document.write( "\"%282x-19%29%2Bx%2Bx=49\"
\n" ); document.write( "\"2x-19%2Bx%2Bx=49\"
\n" ); document.write( "\"4x-19=49\"
\n" ); document.write( "\"4x=49%2B19\"
\n" ); document.write( "\"4x=68\"
\n" ); document.write( "\"x=68%2F4\"
\n" ); document.write( "\"highlight%28x=17%29\"
\n" ); document.write( "Then, \"2x-19=2%2A17-19\"-->\"2x-19=34-19\"\"highlight%282x-19=15%29\"
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