document.write( "Question 939781: Given ST bisects angle RSV
\n" ); document.write( " m of angle RST =2x+3y
\n" ); document.write( " m of angle TSV = 3x-y+2
\n" ); document.write( " m of angle RSV = 80 degrees \r
\n" ); document.write( "\n" ); document.write( "Find x and y. \r
\n" ); document.write( "\n" ); document.write( "I am not sure how y and x separate ? please help! can you show me how to do this?
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Algebra.Com's Answer #572715 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "if \"ST\" bisects angle \"RSV\" means divides angle into two equal parts, angle \"RST\" and angle \"TSV\"
\n" ); document.write( "it means \"m\" <\"RSV\"=\"m\" <\"RST\"+\"m\" <\"TSV\"\r
\n" ); document.write( "\n" ); document.write( " if \"m\" < \"RST+=2x%2B3y\"
\n" ); document.write( " \"m\" < \"TSV+=+3x-y%2B2\"
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\n" ); document.write( "\"m\" < \"RSV+=+80\" degrees \r
\n" ); document.write( "\n" ); document.write( "and if \"m\" <\"RSV\"=\"m\" <\"RST\"+\"m\" <\"TSV\", then\r
\n" ); document.write( "\n" ); document.write( "\"m\" < \"2x%2B3y=40\"........eq.1
\n" ); document.write( "\"m\" < \"+3x-y%2B2=40\"......eq.2
\n" ); document.write( "-----------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "solve the system:
\n" ); document.write( "\"2x%2B3y=40\"........eq.1
\n" ); document.write( "\"+3x-y%2B2=40\"......eq.2....both sides multiply by \"3\"
\n" ); document.write( "-----------------------\r
\n" ); document.write( "\n" ); document.write( "\"2x%2B3y=40\"........eq.1
\n" ); document.write( "\"+9x-3y%2B6=120\"......eq.2.
\n" ); document.write( "------------------------------------add\r
\n" ); document.write( "\n" ); document.write( "\"2x%2Bcross%283y%29%2B9x-cross%283y%29%2B6=40%2B120\"\r
\n" ); document.write( "\n" ); document.write( "\"2x%2B9x%2B6=160\"\r
\n" ); document.write( "\n" ); document.write( "\"11x=160-6\"\r
\n" ); document.write( "\n" ); document.write( "\"11x=154\"\r
\n" ); document.write( "\n" ); document.write( "\"x=154%2F11\"\r
\n" ); document.write( "\n" ); document.write( "\"x=14\"
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\n" ); document.write( "go to \"+3x-y%2B2=40\"......eq.2 substitute \"14\" for \"x\" and solve for \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"+3%2A14-y%2B2=40\"\r
\n" ); document.write( "\n" ); document.write( "\"+42-y%2B2=40\"\r
\n" ); document.write( "\n" ); document.write( "\"+44-40=y\"\r
\n" ); document.write( "\n" ); document.write( "\"+4=y\"\r
\n" ); document.write( "\n" ); document.write( "so, the \"m\" <\"RST\" and \"m\" <\"TSV\" is:\r
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\n" ); document.write( "\n" ); document.write( "\"m\" < \"RST+=2x%2B3y\"=>\"m\" < \"RST+=2%2A14%2B3%2A4\"\"m\" < \"RST+=28%2B12\"=>\"m\" < \"RST+=40\"\r
\n" ); document.write( "\n" ); document.write( "\"m\" < \"TSV+=+3x-y%2B2\"=>\"m\" < \"TSV+=+3%2A14-4%2B2\"=>\"m\" < \"TSV+=+42-4%2B2\"=>\"m\" < \"TSV+=+44-4\"=>\"m\" < \"TSV+=40\"\r
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