document.write( "Question 939682: determine if g is the inverse of f.\r
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\n" ); document.write( "\n" ); document.write( "f(x)=4 + x^2,x≥0; g(x)=√x - 4
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Algebra.Com's Answer #572705 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"f%28x%29=4+%2B+x%5E2\", \"x%3E=0\"; \"g%28x%29=sqrt%28x-4%29\" \r
\n" ); document.write( "\n" ); document.write( "find inverse:\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=4+%2B+x%5E2\".........\"f%28x%29=y\"\r
\n" ); document.write( "\n" ); document.write( "\"y=4+%2B+x%5E2\"..........swap \"x\" and \"y\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=4+%2B+y%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"x-4=y%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"y=sqrt%28x-4%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%5E-1%28x%29=sqrt%28x-4%29\" for \"x%3E=0\"\r
\n" ); document.write( "\n" ); document.write( "so, \"g%28x%29=sqrt%28x-4%29\" in inverse \"f%28x%29=4+%2B+x%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+4+%2B+x%5E2%2C+sqrt%28x-4%29%29+\"\r
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