document.write( "Question 939767: A movie theater charges $10 for adult tickets and $7 for child tickets. On a particular day, they made $1475 in ticket sales. They also know that they sold 170 tickets altogether. This means they must have sold adult tickets and child tickets. \n" ); document.write( "
Algebra.Com's Answer #572699 by mananth(16946)\"\" \"About 
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x= number of adult tickets
\n" ); document.write( "y= number of child tickets
\n" ); document.write( "
\n" ); document.write( "1 x + 1 y = 170 .............1
\n" ); document.write( "
\n" ); document.write( "10 x + 7 y = 1475 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -7
\n" ); document.write( "Multiply (2) by 1
\n" ); document.write( "-7 x -7 y = -1190
\n" ); document.write( "10 x + 7 y = 1475
\n" ); document.write( "Add the two equations
\n" ); document.write( "3 x = 285
\n" ); document.write( "/ 3
\n" ); document.write( "x = 95
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "1 x + 1 y = 170
\n" ); document.write( "95 + y = 170
\n" ); document.write( " y = 170 -95
\n" ); document.write( " y = 75
\n" ); document.write( " y = 75 1
\n" ); document.write( "x= 95 number of adult tickets
\n" ); document.write( "y= 75 number of child tickets
\n" ); document.write( "m.ananth@hotmail.ca
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