document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=939627>Question 939627</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liters of a 20% alcohol should be added to an 80% alcohol solution to obtain 15 liters of a 60%   alcohol solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #572637 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=572637\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many liters of a 20% alcohol should be added to an 80% alcohol solution to obtain 15 liters of a 60% alcohol solution?<BR>\n" );
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document.write( "Equation::<BR>\n" );
document.write( "alch + alch = alch<BR>\n" );
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document.write( "0.20x + 0.80(15-x) = 0.60*15<BR>\n" );
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document.write( "20x + 80*15 - 80x = 60*15<BR>\n" );
document.write( "-60x = -20*15<BR>\n" );
document.write( "x = (1/3)15<BR>\n" );
document.write( "x = 5 liters (amt. of 20% solution needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "----------------- </SPAN>\n" );
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