document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=939625>Question 939625</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In two hours a man can row 26 km downstream but only 14 km upstream. The speed of the stream is? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #572595 by </B><A HREF=/tutors/aboutme.mpl?userid=vicgonzerx><B>vicgonzerx(31)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vicgonzerx><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=vicgonzerx><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=572595\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> St + Mt=26<BR>\n" );
document.write( "S(2) + m(2) = 26<BR>\n" );
document.write( "S + M=13----EQ 1\r<BR>\n" );
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document.write( "M-S=12----EQ 2\r<BR>\n" );
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document.write( "SOLVE M USING 2 EQUATON BY SUBSTRACTION \r<BR>\n" );
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document.write( "M=12.5KM/HR\r<BR>\n" );
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document.write( "SUBSTITUTE M TO EQ 1 TO SOLVE S\r<BR>\n" );
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document.write( "S=0.5KM/HR----------ANSWER====\r<BR>\n" );
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document.write( " </SPAN>\n" );
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