document.write( "Question 939602: A man started driving his car at a certain time from a certain place. On arrival at his destination at the precise appointed time, he said, \"If I had averaged 6 miles per hour faster, I would have been 5 minutes early. But if I had averaged 5 mph slower, I would have been 6 minutes late.\" Find how far he had driven. \n" ); document.write( "
Algebra.Com's Answer #572587 by josgarithmetic(39623)![]() ![]() ![]() You can put this solution on YOUR website! ___________________rate_____________time_____________distance \n" ); document.write( "Faster_____________r+6_____________t-5/60____________d \n" ); document.write( "OnTime______________r_______________t________________d \n" ); document.write( "Slower_____________r-5____________t+6/60_____________d\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Three equations using three unknowns, r, t, d. \n" ); document.write( "Goal is find the value for d.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use the simpler equation to substitute for rt in the Fast and Slow equations, and simplify. If you handle this correctly then you get a system of two equations in r and t. Solve that system for r and t... and you can then evaluate r*t=d. \n" ); document.write( " |