document.write( "Question 939578: The length of a rectangle is 2 m more that the width. The area is 48 m2. Find the dimensions of the
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Algebra.Com's Answer #572585 by srinivas.g(540)\"\" \"About 
You can put this solution on YOUR website!
let width be x meters
\n" ); document.write( "length = 2+x
\n" ); document.write( "area = 48 m^2
\n" ); document.write( "formula: area = length x width
\n" ); document.write( " 48 = (2+x)*x
\n" ); document.write( " 48= 2*x+x*x
\n" ); document.write( " \"48=+2x%2Bx%5E2\"
\n" ); document.write( " move 48 to the right
\n" ); document.write( " \"0=2x%2Bx%5E2-48\"
\n" ); document.write( " \"+x%5E2%2B2x-48=0\"
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B2x%2B-48+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%282%29%5E2-4%2A1%2A-48=196\".
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\n" ); document.write( " Discriminant d=196 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-2%2B-sqrt%28+196+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%282%29%2Bsqrt%28+196+%29%29%2F2%5C1+=+6\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%282%29-sqrt%28+196+%29%29%2F2%5C1+=+-8\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B2x%2B-48\" can be factored:
\n" ); document.write( " \"1x%5E2%2B2x%2B-48+=+1%28x-6%29%2A%28x--8%29\"
\n" ); document.write( " Again, the answer is: 6, -8.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B2%2Ax%2B-48+%29\"

\n" ); document.write( "\n" ); document.write( " x cannot be negative
\n" ); document.write( " hence x= 6
\n" ); document.write( "width (x)= 6 m
\n" ); document.write( " length = 6+2 = 8 m
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