document.write( "Question 939585: A jar filled with nickels and quarters contains a total of 50 coins. The value of all the coins in the jar is $6.50. How many quarters are in the jar. \n" ); document.write( "

Algebra.Com's Answer #572583 by srinivas.g(540) $\"\"$ $\"About$

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1 nickle = 0.05 dollars
\n" ); document.write( "1 quarter =0.25 dollars
\n" ); document.write( "let x be the no of nickles
\n" ); document.write( "let y be the no of quarters
\n" ); document.write( "total no of coins =50
\n" ); document.write( " x+y = 50..............eq(1)
\n" ); document.write( " total worth = $ 6.50
\n" ); document.write( " x*0.05+y*0.25 = $6.50 ..............eq(2)
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Solved by pluggable solver: SOLVE linear system by SUBSTITUTION

Solve:
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We'll use substitution. After moving 1*y to the right, we get:
\n" ); document.write( " $\"1%2Ax+=+50+-+1%2Ay\"$ , or $\"x+=+50%2F1+-+1%2Ay%2F1\"$ . Substitute that
\n" ); document.write( " into another equation:
\n" ); document.write( " $\"0.05%2A%2850%2F1+-+1%2Ay%2F1%29+%2B+0.25%5Cy+=+6.5\"$ and simplify: So, we know that y=20. Since $\"x+=+50%2F1+-+1%2Ay%2F1\"$ , x=30.
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\n" ); document.write( " Answer: $\"system%28+x=30%2C+y=20+%29\"$ .
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\n" ); document.write( "\n" ); document.write( "Result :
\n" ); document.write( " no of quarters = 20
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