document.write( "Question 79731: You invested $10,000 in two stocks paying 9% and 12% annual interest,
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document.write( "respectively. At the end of the year, the total interest from these investments
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document.write( "was $930. How much was invested at each rate? \n" );
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Algebra.Com's Answer #57254 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! .12x+.09(10000-x)=930 \n" ); document.write( ".12x+900-.09x=930 \n" ); document.write( ".03x=30 \n" ); document.write( "x=30/.03 \n" ); document.write( "x=1000 invested @ 12% \n" ); document.write( "10000-1000=9000 invested @ 9% \n" ); document.write( "proof \n" ); document.write( ".12*1000+.09*9000=930 \n" ); document.write( "120+810=930 \n" ); document.write( "930=930 \n" ); document.write( " |