document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=939539>Question 939539</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Through (&#8722;1, &#8722;2);perpendicular to the line 2x + 5y + 1 = 0. What equation satisfies the conditions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #572520 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=572520\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x + 5y + 1 = 0   0r y = (-2/5)x - 1/5<BR>\n" );
document.write( "....<BR>\n" );
document.write( "New Perpendicular Line:  m = 5/2<BR>\n" );
document.write( "***Using point-slope form, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+-+y%5B1%5D+=+highlight_green%28m%29%28x+-+x%5B1%5D%29 ALIGN=MIDDLE  ALT=\"y+-+y%5B1%5D+=+highlight_green%28m%29%28x+-+x%5B1%5D%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >P(-1,-2)<BR>\n" );
document.write( "y + 2 = (5/2)(x+1)<BR>\n" );
document.write( "y = (5/2)x + 5/2 - 4/2<BR>\n" );
document.write( "y = (5/2)x  + 1/2<BR>\n" );
document.write( "0r<BR>\n" );
document.write( "5x - 2y = -2  Standard Form </SPAN>\n" );
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