document.write( "Question 79779: log(Base3)(x-1) -Log(base3)(x+2)=2 \n" ); document.write( "
Algebra.Com's Answer #57245 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
\"log%283%2C%28x-1%29%29+-log%283%2C%28x%2B2%29%29=2\"
\n" ); document.write( "\"log%283%2C%28%28x-1%29%2F%28x%2B2%29%29%29+=2\"\r
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\n" ); document.write( "\n" ); document.write( "\"3%5E2=%28x-1%29%2F%28x%2B2%29+\"
\n" ); document.write( "\"9=%28x-1%29%2F%28x%2B2%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by the common denominator : \"%28x%2B2%29\"
\n" ); document.write( "\"9%28x%2B2%29+=+x-1\"
\n" ); document.write( "\"9x%2B18=x-1\"
\n" ); document.write( "\"9x-x%2B18=-1\"
\n" ); document.write( "\"8x=-1-18\"
\n" ); document.write( "\"8x=-19\"
\n" ); document.write( "\"x=-19%2F8\"\r
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\n" ); document.write( "\n" ); document.write( "However, there is a restriction that you can't have a log of a negative. This answer for \"x=-19%2F8\" gives the log of a negative number in BOTH logarithmic expressions, so it must be rejected. Therefore there is NO SOLUTION to this problem.\r
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\n" ); document.write( "\n" ); document.write( "For additional exercises and detailed solution IN COLOR, see my webpage on logarithms by clicking on my tutor name \"rapaljer\" anywhere in algebra.com. Then look for \"Math in Living Color\", \"College Algebra\", \"Section 4.04 Solving Exponential and Logarithmic Equations.\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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