document.write( "Question 939371: A bag of fast-food sandwiches contains two hamburgers, four cheeseburgers, and three chicken burgers. If Wyatt ordered a cheeseburger and a chicken burger, what is the probability that
\n" ); document.write( "a) the first sandwich selected will be one of his choices?
\n" ); document.write( "b) neither of the first two sandwiches will be among Wyatt's choices?
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Algebra.Com's Answer #572409 by mathmate(429)\"\" \"About 
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\n" ); document.write( "Given: a bag of 2 hamburgers (H), 4 cheeseburgers (C), and 3 chicken burgers (K).\r
\n" ); document.write( "\n" ); document.write( "Solution
\n" ); document.write( "(a) A sandwich is randomly selected from the bag. Find probability of picking one of Wyatt's order -- either a cheeseburger or chicken.
\n" ); document.write( "Assuming random selection, the probability of selecting any burger has equal probability and the probability of success is the ratio #success/#possibilities.
\n" ); document.write( "Success is choosing one of 4C or 3K with a total of 7. The bag contains 9 burgers, which means
\n" ); document.write( "P(C or K) = \"7%2F9\"
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\n" ); document.write( "(b) Two A sandwiches are randomly selected from the bag (assumed without replacement). Find probability of not picking Wyatt's order in both picks.
\n" ); document.write( "The only choice which is not in Wyatt's order is hamburger (H).
\n" ); document.write( "There are two hamburgers in the bag. The first pick is 2 out of 9, and the second pick is 1 (remaining) out of 9. Using the multiplication rule for a two step experiment (without replacement), the probability of picking none of Wyatt's order in the first two picks is
\n" ); document.write( "\"P%28HH%29=%282%2F9%29%281%2F9%29=2%2F81\"
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\n" ); document.write( "Answer:
\n" ); document.write( "(a) probability of picking one of Wyatt's choice is 7/9.
\n" ); document.write( "(b) probability of not picking Wyatt's choice in both of two picks is 2/81.\r
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