document.write( "Question 939380: This is from that episode of Duck Dynasty, so I was just curious. Anyway, here it is:\r
\n" ); document.write( "\n" ); document.write( "Two trucks are traveling 1/4 mile to a store. Truck A is traveling 30 mph, and Truck B is traveling 15 mph. Truck B gets a 20 second head start. Which truck will get to the store first? \n" ); document.write( "
Algebra.Com's Answer #572394 by MathTherapy(10553)\"\" \"About 
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This is from that episode of Duck Dynasty, so I was just curious. Anyway, here it is:\r
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document.write( "Let time it takes slower truck, or Truck B to get to catch-up point, be T 
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document.write( "Then time it takes faster truck, or Truck A to catch-up to truck B is: \"T+-+20%2F3600\", or \"T+-+1%2F180\" \r
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document.write( "Since both had traveled same distance when truck A caught up to Truck B, we then get:
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document.write( "\"15T+=+30%28T+-+1%2F180%29\" 
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document.write( "\"15%28T%29+=+15%282%29%28T+-+1%2F180%29\"
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document.write( "\"T+=+2%28T+-+1%2F180%29\"
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document.write( "\"T+=+2T+-+1%2F90\"
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document.write( "\"T+-+2T+=+-+1%2F90\"
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document.write( "\"-+T+=+%28-+1%29%2F90\" 
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document.write( "- 90T = - 1 ------- Cross-multiplying 
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document.write( "T = \"%28-+1%29%2F%28-+90%29\", or \"1%2F90\" hour
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document.write( "Time taken by Truck B to get to catch-up point = \"%281%2F90%29+%2A+3600\", or 40 seconds
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document.write( "Also, time taken by Truck A to get to catch up-point = \"1%2F90+-+1%2F180\", or \"2%2F180+-+1%2F180\", or \"1%2F180\", or \"%281%2F180%29+%2A+3600\", or 20 seconds \r
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document.write( "The faster truck, or Truck A takes 20 seconds to catch up to Truck B at the \"30%281%2F180%29\", or \"1%2F6-mile\", or 880-foot mark 
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document.write( "Now, since the distance to the store is: \"1%2F4\"-mile, or 1,320 ft, and Truck A caught up to Truck B at the
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document.write( "\"1%2F6\"-mile, or 880-ft mark, it’s obvious that Truck A clearly overtakes Truck B and reaches the store first \n" );
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