document.write( "Question 939388: Mia is 12 years older than Max. 5 years ago their sum was 28. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #572376 by srinivas.g(540)\"\" \"About 
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let x, y be the present ages of Mia and Max\r
\n" ); document.write( "\n" ); document.write( "Mia was 12 years older than Max
\n" ); document.write( " x= y+12
\n" ); document.write( " 5 years ago , mia age = x-5
\n" ); document.write( " 5 years ago ,Max age = y-5
\n" ); document.write( " sum = (x-5)+(y-5)
\n" ); document.write( " =x+y-10
\n" ); document.write( " sum equals to 28
\n" ); document.write( " x+y-10 = 28
\n" ); document.write( " x+y = 28+10
\n" ); document.write( " x+y = 38
\n" ); document.write( " put x= y+12 in above equation
\n" ); document.write( " (y+12)+y = 38
\n" ); document.write( " 2y+12= 38
\n" ); document.write( " 2y =38-12
\n" ); document.write( " 2y = 26
\n" ); document.write( " divide with 2 on both sides
\n" ); document.write( " \"+2y%2F2+=26%2F2\"
\n" ); document.write( " y= 13
\n" ); document.write( " x = 13+12= 25
\n" ); document.write( " Result: Mia's age (x)= 25 years
\n" ); document.write( " Max's age (y)= 13
\n" ); document.write( " \n" ); document.write( "
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