document.write( "Question 79778: Solve the following system of equations using the addition (elimination) method. Be sure to state the solution to the system.
\n" ); document.write( "x+2y=-7
\n" ); document.write( "2x+3y=-12
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Algebra.Com's Answer #57237 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Linear Systems by Addition
We'll solve the system:
\n" ); document.write( " \"1%2Ax+%2B+2%2Ay+=+-7\"
\n" ); document.write( " \"2%2Ax+%2B+3%2Ay+=+-12\"
\n" ); document.write( " by elimination by addition.To eliminate by addition, we need to set both coefficients of x to numbers with changed signs, i.e a and -a. Since in the second equation we have 2 as our coefficient for x, to get -1 we have to multiply all terms of the second equation by \"-1%2F2\" which is equal to -0.5.
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\n" ); document.write( " Multiplying, we get on our second equation:\"%282%2A-0.5%29x+%2B+%283%2A-0.5%29y+=+-12%2A-0.5\"
\n" ); document.write( " \"-1%2Ax+%2B+-1.5%2Ay+=+6\"
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\n" ); document.write( " Adding both equations we get:
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\n" ); document.write( " \"%281%2B-1%29x+%2B+%282%2B-1.5%29y+=+%28-7%2B6%29\"
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\n" ); document.write( " Since 1 and -1 cancel out, we have a linear equation:Therefore, we know that y = -2.
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\n" ); document.write( " Plugging that in into the first equation gives us:
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\n" ); document.write( " \"1%2Ax+%2B+2%2Ay+=+-7\"
\n" ); document.write( " \"1%2Ax+%2B+2%2A-2+=+-7\"
\n" ); document.write( " \"1%2Ax+%2B+-4+=+-7\"
\n" ); document.write( " \"1%2Ax+=+-7+-+-4\"
\n" ); document.write( " \"x+=+%28-7+-+-4%29%2F1\"
\n" ); document.write( " \"x+=+-3%2F1\"
\n" ); document.write( " \"x+=+-3\"
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\n" ); document.write( " Therefore, our answer is:
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\n" ); document.write( " \"system%28+x=-3%2C+y=-2+%29\"

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\n" ); document.write( "\n" ); document.write( "So the solution is (-3,-2)
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