document.write( "Question 939285: A gardener needs 6 bushels of a potting medium of 40% peat moss and 60% vermiculite. He decides to add 100% vermiculite to his current potting medium that is 50% peat moss and 50% vermiculite. The gardener has 5 bushels of the 50% peat moss and 50% vermiculite moss mix. Does he have enough of the 50% peat moss and 50% vermiculite mix to make 6 bushels of the 40% peat moss and 60% vermiculite mix? Explain.
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document.write( "P.S. I am not good at English so it would help me a lot if you can answer this. Thank you. \n" );
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Algebra.Com's Answer #572361 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A gardener needs 6 bushels of a potting medium of 40% peat moss and 60% vermiculite. \n" ); document.write( " He decides to add 100% vermiculite to his current potting medium that is 50% peat moss and 50% vermiculite. \n" ); document.write( " The gardener has 5 bushels of the 50% peat moss and 50% vermiculite moss mix. \n" ); document.write( " Does he have enough of the 50% peat moss and 50% vermiculite mix to make 6 bushels of the 40% peat moss and 60% vermiculite mix? Explain. \n" ); document.write( ": \n" ); document.write( "let x = amt of 100% vermiculite required \n" ); document.write( "then \n" ); document.write( "(6-x) = amt of 50% vermiculite required \n" ); document.write( ": \n" ); document.write( "Write a mixture equation based on the decimal amt of percent vermiculite \n" ); document.write( "x + .50(6-x) = .60(6) \n" ); document.write( "x + 3 - .5x = 3.6 \n" ); document.write( "x - .5x = 3.6 - 3 \n" ); document.write( ".5x = .6 \n" ); document.write( "multiply both sides by 2 \n" ); document.write( "x = 1.2 bushels of the 100% vermiculite required \n" ); document.write( ": \n" ); document.write( "Find how much 50:50 stuff he needs \n" ); document.write( "6 - 1.2 = 4.8 bushels, so he has enough \n" ); document.write( ": \n" ); document.write( "See if that checks out \n" ); document.write( "1.2 + .50(4.8) = .60(6) \n" ); document.write( "1.2 + 2.4 = 3.6 \n" ); document.write( "////////////////////////// \n" ); document.write( " |