document.write( "Question 939230: the hiking club went on a hike one Saturday. in the morning they walked at an average speed of 3 mi/hr; in the afternoon they averaged 2 mi/hr for 1 hr more than the number of hours they had to walk in the morning. How many hours did they have to walk in the morning if they walked a total of 22 miles? \n" ); document.write( "
Algebra.Com's Answer #572295 by TimothyLamb(4379)\"\" \"About 
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x = time walked in the morning (hours)
\n" ); document.write( "y = time walked in the afternoon (hours)
\n" ); document.write( "---
\n" ); document.write( "y = x + 1
\n" ); document.write( "---
\n" ); document.write( "s = d/t
\n" ); document.write( "d = st
\n" ); document.write( "---
\n" ); document.write( "distance in the morning:
\n" ); document.write( "a = 3x
\n" ); document.write( "---
\n" ); document.write( "distance in the afternoon:
\n" ); document.write( "b = 2y
\n" ); document.write( "b = 2(x + 1)
\n" ); document.write( "b = 2x + 2
\n" ); document.write( "---
\n" ); document.write( "total distance:
\n" ); document.write( "a + b = 22
\n" ); document.write( "3x + 2x + 2 = 22
\n" ); document.write( "5x = 20
\n" ); document.write( "x = 4 hours
\n" ); document.write( "---
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