document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=939185>Question 939185</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jayden and Alexa were asked if 6C2 + 6C3 = 7C3 is true. Their calculations showed it was not true, but they both made mistakes in their calculations. Explain and correct their mistakes. I already corrected jaydens mistakes, but i cant figure out how to fix Alexa's. So please help. Alexa added the fractions by using the LCD (least common denominator). <BR>\n" );
document.write( "Step 1   6!   6! <BR>\n" );
document.write( "        --- + --- <BR>\n" );
document.write( "        2!4!  3!3! <BR>\n" );
document.write( "Step 2    6!    4*6! <BR>\n" );
document.write( "        ---- + ----- <BR>\n" );
document.write( "       4*3!3!  4*3!3! <BR>\n" );
document.write( "Step 3   5*6! <BR>\n" );
document.write( "        ------ <BR>\n" );
document.write( "         4*3!3! <BR>\n" );
document.write( "Step 4    7!    7*6!<BR>\n" );
document.write( "         ---- = -----  <BR>\n" );
document.write( "         3!4!   4*3!3! <BR>\n" );
document.write( "Step 5    5*6!           7*6! <BR>\n" );
document.write( "         ----- not equal ----- <BR>\n" );
document.write( "         4*3!3!          4*3!3!<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #572260 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=572260\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6C2 + 6C3 = 7C3 <BR>\n" );
document.write( "(6*5)/(1*2) + (6*5*3/1*2*3) = (7*6*5/1*2*3)<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "Multiply thru by 3! to get: <BR>\n" );
document.write( "3*30 + 90 = 210<BR>\n" );
document.write( "90 + 90 = 210<BR>\n" );
document.write( "false<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "----------------- </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );