document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=939140>Question 939140</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve 2cos2x + cosx &#8722; 1 = 0 for x over the interval [0, 2 3.14  ). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #572187 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=572187\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2cos^2x + cosx - 1 = 0<BR>\n" );
document.write( "(2cosx - 1)(cosx + 1)= 0<BR>\n" );
document.write( "cosx = 1/2  x = pi/3, 5pi/3<BR>\n" );
document.write( "cosx = -1 , x = pi<BR>\n" );
document.write( "(cosx, sinx) Summary Unit Circle<BR>\n" );
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