document.write( "Question 939125: A statistic practitioner took a random sample of 50 observations from a population with a standard deviation of 25 and computed the sample mean to be 100. estimate the population mean with 99% confidence. \n" ); document.write( "
Algebra.Com's Answer #572176 by ewatrrr(24785)\"\" \"About 
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ME = 2.576(25/sqrt(50)) = 9 rounded
\n" ); document.write( "CI: (91,109)
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\n" ); document.write( " = CI z = value
\n" ); document.write( "90% z =1.645
\n" ); document.write( "92% z = 1.751
\n" ); document.write( "95% z = 1.96
\n" ); document.write( "98% z = 2.326
\n" ); document.write( "99% z = 2.576
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