document.write( "Question 939055: in a rhombus PQRS if PQ=3x-7 and QR=x+3 find PS
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Algebra.Com's Answer #572132 by srinivas.g(540)![]() ![]() You can put this solution on YOUR website! In rhombus all sides are equal \n" ); document.write( "PQ=QR \n" ); document.write( "3x-7=x+3 \n" ); document.write( "Move-7 to the right \n" ); document.write( "3x=x+3+7 \n" ); document.write( "3x=x+10 \n" ); document.write( "Move x to the left \n" ); document.write( "3x-x=10 \n" ); document.write( "2x=10 \n" ); document.write( "Divide with 2 on both sides \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Hence PQ=3x-7 \n" ); document.write( " =3*5-7 \n" ); document.write( "=15-7 \n" ); document.write( "=8 \n" ); document.write( "Hence PQ=QR=RS=PS=8 \n" ); document.write( " \n" ); document.write( " |