document.write( "Question 939053: An 112 ounce mixture is created by combining two ethylene solutions. One solution is10% ethylene and the other is 2% ethylene. If the finale mixture is comprised of 7.9% ethylene solution, then how much of the 10% solution was used?
\n" ); document.write( "How do I do this? Thank you and please
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Algebra.Com's Answer #572130 by mathmate(429)\"\" \"About 
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\n" ); document.write( "Method 1: Using unknown x
\n" ); document.write( "step 1.
\n" ); document.write( "using unknown x=volume of 10% (=0.1) solution in ounces
\n" ); document.write( "then volume of 2% (=0.02) solution is 112-x ounces to make 112 ounces of 7.9% (0.079) solution.
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\n" ); document.write( "step 2.
\n" ); document.write( "form the equation that mixes the two ingredients to make a 7.9% solution
\n" ); document.write( "0.1x+0.02(112-x) = 0.079(112)
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\n" ); document.write( "step 3.
\n" ); document.write( "Solve for x
\n" ); document.write( "0.1x+2.24-0.02x = 8.848
\n" ); document.write( "0.08x=6.608
\n" ); document.write( "x=82.6
\n" ); document.write( "Volume of 2% solution = 112-82.6=29.4 ounces
\n" ); document.write( "Answer: 82.6 ounces of 10% solution, and 29.4 ounces of 2% solution.
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\n" ); document.write( "method 2: using proportions
\n" ); document.write( "V(10%):V(2%)=(7.9-2) : (10-7.9)
\n" ); document.write( "=5.9 : 2.1
\n" ); document.write( "Volume of 10% solution = \"112%285.9%2F%285.9%2B2.1%29%29=82.6\" ounces
\n" ); document.write( "Volume of 2% solution = \"112%282.1%2F%285.9%2B2.1%29%29=29.4\" ounces
\n" ); document.write( "Answer: 82.6 ounces of 10% solution, and 29.4 ounces of 2% solution.
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