document.write( "Question 939053: An 112 ounce mixture is created by combining two ethylene solutions. One solution is10% ethylene and the other is 2% ethylene. If the finale mixture is comprised of 7.9% ethylene solution, then how much of the 10% solution was used?
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document.write( "How do I do this? Thank you and please \n" );
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Algebra.Com's Answer #572130 by mathmate(429)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Method 1: Using unknown x \n" ); document.write( "step 1. \n" ); document.write( "using unknown x=volume of 10% (=0.1) solution in ounces \n" ); document.write( "then volume of 2% (=0.02) solution is 112-x ounces to make 112 ounces of 7.9% (0.079) solution. \n" ); document.write( " \n" ); document.write( "step 2. \n" ); document.write( "form the equation that mixes the two ingredients to make a 7.9% solution \n" ); document.write( "0.1x+0.02(112-x) = 0.079(112) \n" ); document.write( " \n" ); document.write( "step 3. \n" ); document.write( "Solve for x \n" ); document.write( "0.1x+2.24-0.02x = 8.848 \n" ); document.write( "0.08x=6.608 \n" ); document.write( "x=82.6 \n" ); document.write( "Volume of 2% solution = 112-82.6=29.4 ounces \n" ); document.write( "Answer: 82.6 ounces of 10% solution, and 29.4 ounces of 2% solution. \n" ); document.write( " \n" ); document.write( "method 2: using proportions \n" ); document.write( "V(10%):V(2%)=(7.9-2) : (10-7.9) \n" ); document.write( "=5.9 : 2.1 \n" ); document.write( "Volume of 10% solution = \n" ); document.write( "Volume of 2% solution = \n" ); document.write( "Answer: 82.6 ounces of 10% solution, and 29.4 ounces of 2% solution. \n" ); document.write( " |