document.write( "Question 938999: Two vehicles are traveling a quarter of a mile. Vehicle a is going 30 mph and vehicle b is going 15 mph. Which vehicle gets there first if vehicle b is given a 20 second head start? Also what are each vehicles' times? \n" ); document.write( "
Algebra.Com's Answer #572113 by josmiceli(19441)\"\" \"About 
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Convert \"+20+\" sec to minutes
\n" ); document.write( "\"+20%2F60+=+1%2F3+\" min
\n" ); document.write( "Convert minutes to hrs
\n" ); document.write( "\"+%281%2F3%29%2A60+=+1%2F180+\" hrs
\n" ); document.write( "---------------------
\n" ); document.write( "Find vehicle b's head start in miles
\n" ); document.write( "\"+d%5B1%5D+=+15%2A%281%2F180%29+\"
\n" ); document.write( "\"+d%5B1%5D+=+1%2F12+\" mi
\n" ); document.write( "------------------
\n" ); document.write( "Start a stopwatch when vehicle a leaves
\n" ); document.write( "Let \"+t+\" = time in hrs on the stopwatch
\n" ); document.write( "when a get to the \"+1%2F4+\" mi mark
\n" ); document.write( "---------------------------------
\n" ); document.write( "a's equation:
\n" ); document.write( "\"+1%2F4+=+30t+\"
\n" ); document.write( "\"+t+=+1%2F120+\" hrs
\n" ); document.write( "\"+t+=+%28+1%2F120+%29%2A3600+\"
\n" ); document.write( "\"+t+=+30+\" sec
\n" ); document.write( "-------------------
\n" ); document.write( "Start a different stopwatch when vehicle a leaves
\n" ); document.write( "Let \"+t%5B1%5D+\" = time in hrs on the stopwatch
\n" ); document.write( "when b gets to the \"+1%2F4+\" mi mark
\n" ); document.write( "b's equation:
\n" ); document.write( "\"+1%2F4+-+1%2F12+=+15t%5B1%5D+\"
\n" ); document.write( "\"+t%5B1%5D+=+%28+3%2F12+-+1%2F12+%29+%2F+15+\"
\n" ); document.write( "\"+t%5B1%5D+=+%28+1%2F6+%29%2F15+\"
\n" ); document.write( "\"+t%5B1%5D+=+1%2F90+\" hr
\n" ); document.write( "\"+t%5B1%5D+=+%28+1%2F90+%29%2A3600+\"
\n" ); document.write( "\"+t%5B1%5D+=+40+\" sec
\n" ); document.write( "---------------------
\n" ); document.write( "a arrives at the 1/4 mi mark first, and
\n" ); document.write( "beats b by \"+40+-+30+=+10+\" sec
\n" ); document.write( "
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