document.write( "Question 939025: find the equation of the circle (standard form)\r
\n" ); document.write( "\n" ); document.write( "the circle has a diameter with endpoints whose coordinates are (7, -2) and (-3, 5).\r
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Algebra.Com's Answer #572091 by lwsshak3(11628)\"\" \"About 
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find the equation of the circle (standard form)
\n" ); document.write( "the circle has a diameter with endpoints whose coordinates are (7, -2) and (-3, 5).
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\n" ); document.write( "Standard form of equation for a circle: (x-h)^2+(y-k)^2=r^2, (h,k)=coordinates of center, r=radius
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\n" ); document.write( "center=midpoint of diameter:(7-3)/2,(-2+5)/2=(2,1.5)
\n" ); document.write( "diameter=√((7+3)^2+(-2-5)^2)=√(100+49)=√149 (distance formula)
\n" ); document.write( "r=√149/2
\n" ); document.write( "r^2=149/4
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\n" ); document.write( "equation: (x-2)^2+(y-1.5)^2=149/4
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