document.write( "Question 939009: A canoe took 4 hours to travel 18 km with the current. On the return trip, the canoe took 6 hours to travel the same distance against the current. When the canoe travels with the current it travels faster than normal. How fast does the canoe travel with the current? One decimal accuracy. \n" ); document.write( "
Algebra.Com's Answer #572090 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
canoe speed =x km
\n" ); document.write( "current speed =y km
\n" ); document.write( "against current 6 hours
\n" ); document.write( "with current 4 hours
\n" ); document.write( "
\n" ); document.write( "Distance against 18 miles distance with 18 km
\n" ); document.write( "t=d/r against current -
\n" ); document.write( "18.00 / ( x - y )= 6.00
\n" ); document.write( "6.00 ( x - y ) = 4.00
\n" ); document.write( "6.00 x - 6.00 y = 18.00 ....................1
\n" ); document.write( "
\n" ); document.write( "18.00 / ( x + y )= 4.00
\n" ); document.write( "4.00 ( x + y ) = 18.00
\n" ); document.write( "4.00 x + 4.00 y = 18.00 ...............2
\n" ); document.write( "Multiply (1) by 4.00
\n" ); document.write( "Multiply (2) by 6.00
\n" ); document.write( "we get
\n" ); document.write( "24.00 x + -24.00 y = 72.00
\n" ); document.write( "24.00 x + 24.00 y = 108.00
\n" ); document.write( "48.00 x = 180.00
\n" ); document.write( "/ 48.00
\n" ); document.write( "x = 3.75 km/h
\n" ); document.write( "
\n" ); document.write( "plug value of x in (1) y
\n" ); document.write( "6.00 x -6.00 y = 18.00
\n" ); document.write( "22.50 -6.00 -22.50 = 18.00
\n" ); document.write( "-6.00 y = 18.00
\n" ); document.write( "-6.00 y = -4.50 km/h
\n" ); document.write( " y = 0.75
\n" ); document.write( "canoe speed 3.75 km/h
\n" ); document.write( "current speed 0.75 km/h
\n" ); document.write( "
\n" ); document.write( "With current speed = 3.75+0.75 = 4.5 km/h
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( " \n" ); document.write( "
\n" );