document.write( "Question 79700: To solve 1/x-3+ 1/x+3 = 10/x^2-9, which step would result?\r
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document.write( "I got: (x+3)+(x+3) = 10\r
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document.write( "Is this correct?
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document.write( "Thanks~ \n" );
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Algebra.Com's Answer #57206 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Given: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Don't think you are correct, but let's check your answer. You got: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Remove the parentheses and this becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Add like terms on the left side and you get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Subtract 6 from both sides and you get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Then divide both sides by 2 and you finally have \n" ); document.write( "original equation and substitute 2 for x it becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Doing the math in the 3 denominators results in: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "and this further simplifies to: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "which becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "by adding +1 to both sides this becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "That doesn't look too good. \n" ); document.write( ". \n" ); document.write( "Let's go back to the original problem and work it out: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "You probably recognized that the denominator on the right side factors to: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Substitute that into the equation and it becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Now multiply all the terms on both sides by \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "cross out the common terms in the denominator and the numerator: \n" ); document.write( ".\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "and the equation becomes: \n" ); document.write( ".\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Remove the parentheses: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Combine the like terms on the left side (note +3 -3 = 0) and you get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Finally divide both sides by 2 and you get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Now let's check the answer. Return to the original equation and substitute 5 for x to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "That works ... so the answer is x = 5 \n" ); document.write( ". \n" ); document.write( "Hope this helps you to find your mistake. \n" ); document.write( " |