document.write( "Question 938885: There are a total of 23 nickels and dimes. Together, they make $1.95. How many of the coins are nickles, and how many are dimes? \n" ); document.write( "

Algebra.Com's Answer #572043 by mathmate(429) $\"\"$ $\"About$

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Method 1:
\n" ); document.write( "Solve using a single equation:
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\n" ); document.write( "Let d=number of nickels (worth 10 cents each)
\n" ); document.write( "then 23-d = number of nickels (worth 5 cents each)
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\n" ); document.write( "We have total value
\n" ); document.write( "10d + 5(23-d) = 195 cents
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\n" ); document.write( "Distribute and group like terms
\n" ); document.write( "10d + 115 -5d = 195
\n" ); document.write( "5d = 195-115
\n" ); document.write( "5d = 80
\n" ); document.write( "d=16
\n" ); document.write( "Answer: So there are 16 dimes and 23-16=7 nickels.
\n" ); document.write( "Check: 16(10)+7(5)=160+35=195 cents = $1.95 checks.
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\n" ); document.write( "Method 2: (can be done mentally)
\n" ); document.write( "Assume all coins are dimes, then value = 23*10 = 230 cents.
\n" ); document.write( "There is an excess of 230-195=35 cents.
\n" ); document.write( "So number of nickels = 35 cents / (10-5) cents = 7
\n" ); document.write( "Number of dimes = 23-7 = 16 as as before.
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