document.write( "Question 938774: Tom is 6 times as old as todd. In 5 years Tom's age will be 31 years more than 2 times as old as todd. How old is Tom? \n" ); document.write( "
Algebra.Com's Answer #571937 by algebrahouse.com(1659)\"\" \"About 
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x = Todd's age now
\n" ); document.write( "6x = Tom's age now\r
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\n" ); document.write( "\n" ); document.write( "x + 5 = Todd's age in 5 years {added 5 onto current age}
\n" ); document.write( "6x + 5 = Tom's age in 5 years {added 5 onto current age}\r
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\n" ); document.write( "\n" ); document.write( "6x + 5 = 2(x + 5) + 31 {in 5 years, Tom will be 31 more than 2 times Todd}
\n" ); document.write( "6x + 5 = 2x + 10 + 31 {used distributive property}
\n" ); document.write( "4x + 5 = 2x + 41 {combined like terms}
\n" ); document.write( "4x = 36 {subtracted 2x and 5 from each side}
\n" ); document.write( "x = 9 {divided each side by 2}
\n" ); document.write( "6x = 54 {substituted 13, in for x, into 6x}\r
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\n" ); document.write( "\n" ); document.write( "Tom is 54
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