document.write( "Question 938729: find the equation of a circle with center at (-4,2) and tangent to the line 2x-y+2=0 \n" ); document.write( "
Algebra.Com's Answer #571912 by ewatrrr(24785)\"\" \"About 
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Circle: \"%28x%2B4%29%5E2+%2B+%28y-2%29%5E2+=+r%5E2\"
\n" ); document.write( "tangent to...
\n" ); document.write( "y = 2x + 2
\n" ); document.write( "...
\n" ); document.write( "Line perpendicular thru C(-4,2)
\n" ); document.write( "y - 2 = (-1/2)(x + 4)
\n" ); document.write( "y = (-1/2)x
\n" ); document.write( "...
\n" ); document.write( "(-1/2)x = 2x + 2
\n" ); document.write( "-2 = (5/2)x
\n" ); document.write( "(-4/5) = x and y = 2/5 \"%28-1%2F2%29%28-4%2F5%29\"
\n" ); document.write( "...
\n" ); document.write( "C(-4,2)
\n" ); document.write( "(-4/5, 2/5)
\n" ); document.write( "r^2 = \"+%28x%5B1%5D-x%5B2%5D%29%5E2%2B+%28y%5B1%5D-y%5B2%5D%29%5E2++\"
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\n" ); document.write( "r^2 = \"%28-16%2F5%29%5E2+%2B+%288%2F5%29%5E2\" = 320/25
\n" ); document.write( "\"%28x%2B4%29%5E2+%2B+%28y-2%29%5E2+=+r%5E2\"
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