document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=79714>Question 79714</A>: <I><SPAN STYLE=\"word-break: break-all;\"> REVIEW\r<BR>\n" );
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document.write( "41: What is the equation of the line with slope 2/3 and passes through the midpoint of the segment joining points (-1, 6) and (-7, -4)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #57191 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=57191\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE MIDPOINT OF THE LINE THROUGH (-1,6) & (-7,-4) IS<BR>\n" );
document.write( "(7-1)/2=6/2=3 FOR THE X POINT<BR>\n" );
document.write( "(6+4)/2=10/2=5 FOR THE Y POINT<BR>\n" );
document.write( "NOW WE USE THESE 2 POINTS AND THE GIVEN SLOPE OF 2/3 & SOLVE FOR THE Y INTERCEPT(b)<BR>\n" );
document.write( "5=2/3*3+b<BR>\n" );
document.write( "b=5-6/3<BR>\n" );
document.write( "b=(15-6)/3<BR>\n" );
document.write( "b=9/3 <BR>\n" );
document.write( "b=3 THUS THE EQUATION IS<BR>\n" );
document.write( "Y=2X/3+3<BR>\n" );
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