document.write( "Question 10851: Find the real solution of the equation $\"+x%5E3-2x%5E2%2Bx-2=0+\"$ \n" ); document.write( "

Algebra.Com's Answer #5719 by Earlsdon(6294) $\"\"$ $\"About$

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$\"x%5E3+-+2x%5E2+%2B+x+-+2+=+0\"$ Factor.\r
\n" ); document.write( "\n" ); document.write( " $\"%28x+-+2%29%28x%5E2+%2B+1%29+=+0\"$ Apply the zero product principle.\r
\n" ); document.write( "\n" ); document.write( " $\"x+-+2+=+0\"$ or $\"x%5E2+%2B+1+=+0\"$ \r
\n" ); document.write( "\n" ); document.write( "If $\"x+=+-2\"$ then $\"x+=+2\"$ A real root.\r
\n" ); document.write( "\n" ); document.write( "If $\"x%5E2+%2B+1+=+0\"$ then $\"x%5E2+=+-1\"$ and x = +- $\"sqrt%28-1%29\"$ Two imaginary roots.
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