document.write( "Question 938649: Hello,
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document.write( "I have been stuck on this problem for over an hour. Any help would be greatly appreciated!\r
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document.write( "A certain ore yields an average of 61% iron. How much ore is needed to obtain 1,220 lb of iron?\r
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document.write( "I know the answer is 2,000 but can't figure out how to get there. \n" );
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Algebra.Com's Answer #571848 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 61% yield\r \n" ); document.write( "\n" ); document.write( "If you need 61 lbs you need to have 100 lbs of ore\r \n" ); document.write( "\n" ); document.write( "to get 1220 lbs \r \n" ); document.write( "\n" ); document.write( "you need 100/61 *1220 = 2000 lbs \n" ); document.write( " \n" ); document.write( " |