document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=938634>Question 938634</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given two consecutive integers. The sum of 3 times the 1st integer and four times the 2nd integer is 95. Find the integers.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #571839 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=571839\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x and y are the integers\r<BR>\n" );
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document.write( "\"Given two consecutive integers\" ----> y = x+1\r<BR>\n" );
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document.write( "\"The sum of 3 times the 1st integer and four times the 2nd integer is 95\" ---> 3x+4y = 95\r<BR>\n" );
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document.write( "3x+4y = 95\r<BR>\n" );
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document.write( "3x+4(x+1) = 95 ... replace y with x+1\r<BR>\n" );
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document.write( "3x + 4x + 4 = 95\r<BR>\n" );
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document.write( "7x + 4 = 95\r<BR>\n" );
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document.write( "I'll let you finish up. </SPAN>\n" );
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