document.write( "Question 938559: the perimeter of a rectangle is 48. The width is 2 more than half the length. find the dimensions
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Algebra.Com's Answer #571797 by algebrahouse.com(1659)\"\" \"About 
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x = length
\n" ); document.write( "(x/2) + 2 = width {width is 2 more than half the length}\r
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\n" ); document.write( "\n" ); document.write( "Perimeter of a rectangle is 2(width) + 2(length}\r
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\n" ); document.write( "\n" ); document.write( "2x + 2[(x/2) + 2] = 48 {substituted width and length into perimeter formula}
\n" ); document.write( "2x + x + 4 = 48 {used distributive property}
\n" ); document.write( "3x + 4 = 48 {combined like terms}
\n" ); document.write( "3x = 44 {subtracted 4 from each side}
\n" ); document.write( "x = 44/3 {divided each side by 3}
\n" ); document.write( "(x/2) + 2 = 28/3 {substituted 44/3, in for x, into (x/2) + 2}\r
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\n" ); document.write( "\n" ); document.write( "length is 44/3
\n" ); document.write( "width is 28/3
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